TYPE - 1
Raju can do a piece of work in 20 days. Sanjeev do the same in 30 days. The Number of days required to finish the work if they worked together?
1) 6 days
2) 9 days
3) 12 days
4) 14 days
5) None of these
Short cut method
If P can do a work in x days and Q and do the same work in y days P and Q can do the work in xy/x+y days
xy/x+y = 20x30/20+30 = 20x30/50 = 12 days
Ans : (3)
TYPE - 2
Gopi and Sunder can make a cot in 24 days. Gopi alone can make it in 36 days. Then Sunder alone can make it in?
1) 40 days
2) 72 days
3) 48 days
4) 56 days
5) None of these
Short cut method
If P and Q can do a piece of work in x days, P alone can do it in y days the Q alone can do the work in xy/y-x days
xy/y-x = 24x36/36-24 = 24x36/12 = 72 days
Ans : (2)
TYPE - 3
Geetha can finish a work in 10 days. Suma can do it in 12 days. Shija can do the same work in 15 days. Then number of days required to finish the work if Geetha, Suma and Shija do the work together?
1) 8 days
2) 4 days
3) 6 days
4) 9 days
5) None of these
Short cut method
If P can do a work in x days Q can do it in y days and R can do the work in Z days. Then they together can finish the work in
xyz/xy+yz+zx days
10x12x15 / 10x12 + 12x15 + 15x10 = 10 x 12 x 15/ 450 = 4 days
Ans : (2)
TYPE - 4
Suresh and Renesh can do a work in 10 days. Renesh and Sreenesh can finist the work in 12 days. Sreenesh and Jagetheesh can do the work in 15 days. The number of days required to finish the work if they worked together?
1) 4 days
2) 7 days
3) 6 2/3 days
4) 8 days
5) None of these
Short cut method
If P and Q can do a work in x days, Q and R can do it in Y days, R and P in Z days, then they together can finish the work in
2xyz/xy+yz+zx
2 x 10 x 12 x 15/ 10x12 + 12x15 + 15x10
2x10x12x15 / 450 = 8 days
Ans : (4)
TYPE - 5
If 25 men can make a oad in 35 days, then 7 men can make the road in.
1) 100 days
2) 95 days
3) 120 days
4) 125 days
5) None of these
Short cut method
If M1 men do a work in D1 days and M2 can do a work in D2 days
M1 D1 = M2 D2
25 x 35 = 7 x D2
D2 = 25 x 35/7 = 125 days
Ans : (4)
TYPE - 6
10 men can finish a work in 21 days by working 8 hours daily. The number of days required to finish the work by 16 men working 7 hours daily
1) 15
2) 16
3) 20
4) 24
5) None of these
Short cut method
If M1 men can do a work in D1 days by working H1 hours daily and M2 can do the same work in D2 days by working H2 hours daily then
M1 D1 H1 = M2 D2 H2
10x8x21 = 16xD2x7
D2 = 10x8x21/16x7 = 15 days
Ans : (1)
TYPE - 7
10 Carpenters by working 8 hours daily can make 14 tables in 21 days. Then number of tables that can be made by 8 carpentes in 15 days by working 7 hours daily.
1) 28
2) 7
3) 10
4) 16
5) None of these
Short cut method
M1 men can do W1 work in D1 days by working H1 hours and M2 men can do W2 work in D2 days by working H2 hours then
M1D1H1/W1 = M2D2H2/W2
10x21x8/14 = 8x15x7/W2
W2 = 8x15x7x14/10x21x8 = 7 tables
Ans : (2)
TYPE - 8
2 men or 4 women can do a work in 28 days. The 4 men and 8 women togethe can finish the work in
1) 8 days
2) 7 days
3) 14 days
4) 16 days
5) None of these
Short cut method
P men or Q women can finish a work in x days, then M men and N women can finish the work in
PQX/PN+QM days
2x4x28/2x8+4x4 =
2x4x28/32 = 7 days
Ans : (2)
TYPE - 9
Gopu can do a work in 8 days. Suman can do it in 12 days and Sujith can do it in 18 days. They together worked and finished a work. Their remunaration should be divided in the ratio
1) 1:2:3
2) 3:4:7
3) 10:11:12
4) 9:6:4
5) None of these
Short cut method
If P can do a work in x days Q in y days and R in z days. If they worked together their remunaration should be divided in the ratio
1/x:1/y:1/z
1/8:1/12:1/18
LCM of 8,12,18 = 72
72 x 1/8 : 72 x 1/12 : 72 x 1/18
= 9:6:4
Ans : (4)
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